Base | Representation |
---|---|
bin | 10110001110100110… |
… | …11101101011110001 |
3 | 1010210200100220211012 |
4 | 23013103131223301 |
5 | 143420011443042 |
6 | 5252100400305 |
7 | 601504541504 |
oct | 130723355361 |
9 | 33720326735 |
10 | 11933702897 |
11 | 507429a686 |
12 | 23906a6095 |
13 | 11824c157c |
14 | 812cc113b |
15 | 49ca26e82 |
hex | 2c74ddaf1 |
11933702897 has 4 divisors (see below), whose sum is σ = 11984920740. Its totient is φ = 11882485056.
The previous prime is 11933702887. The next prime is 11933702903. The reversal of 11933702897 is 79820733911.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1060218721 + 10873484176 = 32561^2 + 104276^2 .
It is a cyclic number.
It is not a de Polignac number, because 11933702897 - 222 = 11929508593 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11933702827) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25608572 + ... + 25609037.
It is an arithmetic number, because the mean of its divisors is an integer number (2996230185).
Almost surely, 211933702897 is an apocalyptic number.
It is an amenable number.
11933702897 is a deficient number, since it is larger than the sum of its proper divisors (51217843).
11933702897 is an equidigital number, since it uses as much as digits as its factorization.
11933702897 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51217842.
The product of its (nonzero) digits is 571536, while the sum is 50.
The spelling of 11933702897 in words is "eleven billion, nine hundred thirty-three million, seven hundred two thousand, eight hundred ninety-seven".
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