Base | Representation |
---|---|
bin | 10110001111011010… |
… | …10110101010000001 |
3 | 1010211011010201210002 |
4 | 23013231112222001 |
5 | 143423231133412 |
6 | 5252502045345 |
7 | 601616326532 |
oct | 130755265201 |
9 | 33734121702 |
10 | 11940489857 |
11 | 507810583a |
12 | 2392a19855 |
13 | 1183a2981a |
14 | 813b6a689 |
15 | 49d417dc2 |
hex | 2c7b56a81 |
11940489857 has 4 divisors (see below), whose sum is σ = 12013744560. Its totient is φ = 11867235156.
The previous prime is 11940489853. The next prime is 11940489877. The reversal of 11940489857 is 75898404911.
11940489857 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11940489857 - 22 = 11940489853 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11940489853) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 36627107 + ... + 36627432.
It is an arithmetic number, because the mean of its divisors is an integer number (3003436140).
Almost surely, 211940489857 is an apocalyptic number.
It is an amenable number.
11940489857 is a deficient number, since it is larger than the sum of its proper divisors (73254703).
11940489857 is an equidigital number, since it uses as much as digits as its factorization.
11940489857 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73254702.
The product of its (nonzero) digits is 2903040, while the sum is 56.
The spelling of 11940489857 in words is "eleven billion, nine hundred forty million, four hundred eighty-nine thousand, eight hundred fifty-seven".
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