119445553 has 4 divisors (see below), whose sum is σ = 126471780. Its totient is φ = 112419328.

The previous prime is 119445541. The next prime is 119445589. The reversal of 119445553 is 355544911.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 355544911 = 1759 ⋅202129.

It can be written as a sum of positive squares in 2 ways, for example, as 109160704 + 10284849 = 10448^2 + 3207^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-119445553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (119445253) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3513088 + ... + 3513121.

It is an arithmetic number, because the mean of its divisors is an integer number (31617945).

Almost surely, 2^119445553 is an apocalyptic number.

It is an amenable number.

119445553 is a deficient number, since it is larger than the sum of its proper divisors (7026227).

119445553 is an equidigital number, since it uses as much as digits as its factorization.

119445553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7026226.

The product of its digits is 54000, while the sum is 37.

The square root of 119445553 is about 10929.1149229935. The cubic root of 119445553 is about 492.4815841671.

The spelling of 119445553 in words is "one hundred nineteen million, four hundred forty-five thousand, five hundred fifty-three".