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119570204161 = 644511855211
BaseRepresentation
bin110111101011011110…
…0001000011000000001
3102102122001102201110001
41233112330020120001
53424334433013121
6130532500240001
711432026652212
oct1572674103001
9372561381401
10119570204161
1146789299151
121b20b9a0001
13b3771429c5
145b04227409
15319c3a8991
hex1bd6f08601

119570204161 has 4 divisors (see below), whose sum is σ = 119572123824. Its totient is φ = 119568284500.

The previous prime is 119570204153. The next prime is 119570204177. The reversal of 119570204161 is 161402075911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 119570204161 - 23 = 119570204153 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 119570204161.

It is not an unprimeable number, because it can be changed into a prime (119570207161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 863155 + ... + 992056.

It is an arithmetic number, because the mean of its divisors is an integer number (29893030956).

Almost surely, 2119570204161 is an apocalyptic number.

It is an amenable number.

119570204161 is a deficient number, since it is larger than the sum of its proper divisors (1919663).

119570204161 is an equidigital number, since it uses as much as digits as its factorization.

119570204161 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1919662.

The product of its (nonzero) digits is 15120, while the sum is 37.

The spelling of 119570204161 in words is "one hundred nineteen billion, five hundred seventy million, two hundred four thousand, one hundred sixty-one".

Divisors: 1 64451 1855211 119570204161