119801356673 has 4 divisors (see below), whose sum is σ = 120047355840. Its totient is φ = 119555357508.

The previous prime is 119801356657. The next prime is 119801356691. The reversal of 119801356673 is 376653108911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 119801356673 - 2⁴ = 119801356657 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (119801356603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 122998853 + ... + 122999826.

It is an arithmetic number, because the mean of its divisors is an integer number (30011838960).

Almost surely, 2^119801356673 is an apocalyptic number.

It is an amenable number.

119801356673 is a deficient number, since it is larger than the sum of its proper divisors (245999167).

119801356673 is an equidigital number, since it uses as much as digits as its factorization.

119801356673 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 245999166.

The product of its (nonzero) digits is 816480, while the sum is 50.

The spelling of 119801356673 in words is "one hundred nineteen billion, eight hundred one million, three hundred fifty-six thousand, six hundred seventy-three".