11982073 has 4 divisors (see below), whose sum is σ = 11989648. Its totient is φ = 11974500.

The previous prime is 11982071. The next prime is 11982101. The reversal of 11982073 is 37028911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11982073 - 2¹ = 11982071 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11982071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 411 + ... + 4912.

It is an arithmetic number, because the mean of its divisors is an integer number (2997412).

Almost surely, 2^11982073 is an apocalyptic number.

It is an amenable number.

11982073 is a deficient number, since it is larger than the sum of its proper divisors (7575).

11982073 is an equidigital number, since it uses as much as digits as its factorization.

11982073 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7574.

The product of its (nonzero) digits is 3024, while the sum is 31.

The square root of 11982073 is about 3461.5131084542. The cubic root of 11982073 is about 228.8287845121.

The spelling of 11982073 in words is "eleven million, nine hundred eighty-two thousand, seventy-three".