119831238481 has 4 divisors (see below), whose sum is σ = 125041292352. Its totient is φ = 114621184612.

The previous prime is 119831238479. The next prime is 119831238487. The reversal of 119831238481 is 184832138911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 119831238481 - 2¹ = 119831238479 is a prime.

It is a super-2 number, since 2×119831238481² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (119831238487) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2605026901 + ... + 2605026946.

It is an arithmetic number, because the mean of its divisors is an integer number (31260323088).

Almost surely, 2^119831238481 is an apocalyptic number.

It is an amenable number.

119831238481 is a deficient number, since it is larger than the sum of its proper divisors (5210053871).

119831238481 is an equidigital number, since it uses as much as digits as its factorization.

119831238481 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5210053870.

The product of its digits is 331776, while the sum is 49.

The spelling of 119831238481 in words is "one hundred nineteen billion, eight hundred thirty-one million, two hundred thirty-eight thousand, four hundred eighty-one".