11989403 has 4 divisors (see below), whose sum is σ = 12694680. Its totient is φ = 11284128.

The previous prime is 11989387. The next prime is 11989409. The reversal of 11989403 is 30498911.

11989403 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11989403 - 2⁴ = 11989387 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11989409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 352613 + ... + 352646.

It is an arithmetic number, because the mean of its divisors is an integer number (3173670).

Almost surely, 2^11989403 is an apocalyptic number.

11989403 is a deficient number, since it is larger than the sum of its proper divisors (705277).

11989403 is an equidigital number, since it uses as much as digits as its factorization.

11989403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 705276.

The product of its (nonzero) digits is 7776, while the sum is 35.

The square root of 11989403 is about 3462.5717321090. The cubic root of 11989403 is about 228.8754367921.

It can be divided in two parts, 1198 and 9403, that added together give a palindrome (10601).

The spelling of 11989403 in words is "eleven million, nine hundred eighty-nine thousand, four hundred three".