Base | Representation |
---|---|
bin | 110111110101110100… |
… | …1110000111001000001 |
3 | 102110112021022220002111 |
4 | 1233223221300321001 |
5 | 3431042413222123 |
6 | 131031152415321 |
7 | 11443446503350 |
oct | 1575351607101 |
9 | 373467286074 |
10 | 119917710913 |
11 | 46947470110 |
12 | 1b2a8247541 |
13 | b4011350c0 |
14 | 5b38445997 |
15 | 31bcb4d90d |
hex | 1beba70e41 |
119917710913 has 16 divisors (see below), whose sum is σ = 161008396416. Its totient is φ = 86254496640.
The previous prime is 119917710889. The next prime is 119917710919. The reversal of 119917710913 is 319017719911.
It is not a de Polignac number, because 119917710913 - 217 = 119917579841 is a prime.
It is a super-2 number, since 2×1199177109132 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (119917710919) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 59897956 + ... + 59899957.
It is an arithmetic number, because the mean of its divisors is an integer number (10063024776).
Almost surely, 2119917710913 is an apocalyptic number.
119917710913 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
119917710913 is a deficient number, since it is larger than the sum of its proper divisors (41090685503).
119917710913 is a wasteful number, since it uses less digits than its factorization.
119917710913 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 119797944.
The product of its (nonzero) digits is 107163, while the sum is 49.
The spelling of 119917710913 in words is "one hundred nineteen billion, nine hundred seventeen million, seven hundred ten thousand, nine hundred thirteen".
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