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11992599899 = 71713228557
BaseRepresentation
bin10110010101101000…
…01000110101011011
31010221210012012022122
423022310020311123
5144030101144044
65302003011455
7603121263050
oct131264106533
933853165278
1011992599899
1150a4567895
1223a8369b8b
131191773477
1481aa53027
154a2cacdee
hex2cad08d5b

11992599899 has 4 divisors (see below), whose sum is σ = 13705828464. Its totient is φ = 10279371336.

The previous prime is 11992599893. The next prime is 11992599923. The reversal of 11992599899 is 99899529911.

11992599899 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11992599899 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11992599893) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 856614272 + ... + 856614285.

It is an arithmetic number, because the mean of its divisors is an integer number (3426457116).

Almost surely, 211992599899 is an apocalyptic number.

11992599899 is a deficient number, since it is larger than the sum of its proper divisors (1713228565).

11992599899 is an equidigital number, since it uses as much as digits as its factorization.

11992599899 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1713228564.

The product of its digits is 42515280, while the sum is 71.

The spelling of 11992599899 in words is "eleven billion, nine hundred ninety-two million, five hundred ninety-nine thousand, eight hundred ninety-nine".

Divisors: 1 7 1713228557 11992599899