11993760833 has 4 divisors (see below), whose sum is σ = 11995127808. Its totient is φ = 11992393860.

The previous prime is 11993760799. The next prime is 11993760859. The reversal of 11993760833 is 33806739911.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11993760833 - 2¹⁰ = 11993759809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11993760733) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 670241 + ... + 687902.

It is an arithmetic number, because the mean of its divisors is an integer number (2998781952).

Almost surely, 2^11993760833 is an apocalyptic number.

It is an amenable number.

11993760833 is a deficient number, since it is larger than the sum of its proper divisors (1366975).

11993760833 is an equidigital number, since it uses as much as digits as its factorization.

11993760833 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1366974.

The product of its (nonzero) digits is 734832, while the sum is 50.

The spelling of 11993760833 in words is "eleven billion, nine hundred ninety-three million, seven hundred sixty thousand, eight hundred thirty-three".