Base | Representation |
---|---|
bin | 10110010110100000… |
… | …11101001101101011 |
3 | 1010222022011100110020 |
4 | 23023100131031223 |
5 | 144034001222103 |
6 | 5302430051523 |
7 | 603241341654 |
oct | 131320351553 |
9 | 33868140406 |
10 | 12000023403 |
11 | 50a8778215 |
12 | 23aa949ba3 |
13 | 1193172384 |
14 | 81ba2652b |
15 | 4a3777753 |
hex | 2cb41d36b |
12000023403 has 4 divisors (see below), whose sum is σ = 16000031208. Its totient is φ = 8000015600.
The previous prime is 12000023389. The next prime is 12000023447. The reversal of 12000023403 is 30432000021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12000023403 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12000063403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2000003898 + ... + 2000003903.
It is an arithmetic number, because the mean of its divisors is an integer number (4000007802).
Almost surely, 212000023403 is an apocalyptic number.
12000023403 is a deficient number, since it is larger than the sum of its proper divisors (4000007805).
12000023403 is an equidigital number, since it uses as much as digits as its factorization.
12000023403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4000007804.
The product of its (nonzero) digits is 144, while the sum is 15.
Adding to 12000023403 its reverse (30432000021), we get a palindrome (42432023424).
The spelling of 12000023403 in words is "twelve billion, twenty-three thousand, four hundred three".
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