Base | Representation |
---|---|
bin | 1010111010011111111110… |
… | …0010111010100000000011 |
3 | 1120111012102202120121110021 |
4 | 2232213333202322200003 |
5 | 3033102232014002243 |
6 | 41304441205514311 |
7 | 2345660301340444 |
oct | 256477742724003 |
9 | 46435382517407 |
10 | 12000131000323 |
11 | 390725511a334 |
12 | 1419857712997 |
13 | 6907b889877b |
14 | 2d6b4915d2cb |
15 | 15c23e69a6ed |
hex | ae9ff8ba803 |
12000131000323 has 16 divisors (see below), whose sum is σ = 12813455001600. Its totient is φ = 11211120797184.
The previous prime is 12000131000317. The next prime is 12000131000339. The reversal of 12000131000323 is 32300013100021.
It is a cyclic number.
It is not a de Polignac number, because 12000131000323 - 233 = 11991541065731 is a prime.
It is a super-2 number, since 2×120001310003232 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12000131000297 and 12000131000306.
It is not an unprimeable number, because it can be changed into a prime (12000131000303) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38011278 + ... + 38325676.
It is an arithmetic number, because the mean of its divisors is an integer number (800840937600).
Almost surely, 212000131000323 is an apocalyptic number.
12000131000323 is a deficient number, since it is larger than the sum of its proper divisors (813324001277).
12000131000323 is a wasteful number, since it uses less digits than its factorization.
12000131000323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 353058.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 12000131000323 its reverse (32300013100021), we get a palindrome (44300144100344).
The spelling of 12000131000323 in words is "twelve trillion, one hundred thirty-one million, three hundred twenty-three", and thus it is an aban number.
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