12000133202131 has 4 divisors (see below), whose sum is σ = 12003562795000. Its totient is φ = 11996703609264.

The previous prime is 12000133202093. The next prime is 12000133202143. The reversal of 12000133202131 is 13120233100021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12000133202131 is a prime.

It is a super-2 number, since 2×12000133202131² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12000133202099 and 12000133202108.

It is not an unprimeable number, because it can be changed into a prime (12000133202231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1714791186 + ... + 1714798183.

It is an arithmetic number, because the mean of its divisors is an integer number (3000890698750).

Almost surely, 2^{12000133202131} is an apocalyptic number.

12000133202131 is a deficient number, since it is larger than the sum of its proper divisors (3429592869).

12000133202131 is an equidigital number, since it uses as much as digits as its factorization.

12000133202131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3429592868.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 12000133202131 its reverse (13120233100021), we get a palindrome (25120366302152).

The spelling of 12000133202131 in words is "twelve trillion, one hundred thirty-three million, two hundred two thousand, one hundred thirty-one".