1200014315 has 4 divisors (see below), whose sum is σ = 1440017184. Its totient is φ = 960011448.

The previous prime is 1200014297. The next prime is 1200014341. The reversal of 1200014315 is 5134100021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5134100021 = 1259 ⋅4077919.

It is a cyclic number.

It is not a de Polignac number, because 1200014315 - 2⁶ = 1200014251 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200014293 and 1200014302.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120001427 + ... + 120001436.

It is an arithmetic number, because the mean of its divisors is an integer number (360004296).

Almost surely, 2^1200014315 is an apocalyptic number.

1200014315 is a deficient number, since it is larger than the sum of its proper divisors (240002869).

1200014315 is an equidigital number, since it uses as much as digits as its factorization.

1200014315 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 240002868.

The product of its (nonzero) digits is 120, while the sum is 17.

The square root of 1200014315 is about 34641.2227699889. Note that the first 3 decimals coincide. The cubic root of 1200014315 is about 1062.6627947095.

Adding to 1200014315 its reverse (5134100021), we get a palindrome (6334114336).

The spelling of 1200014315 in words is "one billion, two hundred million, fourteen thousand, three hundred fifteen".