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1200020123113 = 7171431446159
BaseRepresentation
bin10001011101100110110…
…001011110110111101001
311020201110110120110200221
4101131212301132313221
5124130120122414423
62315140455530041
7152461421514010
oct21354661366751
94221413513627
101200020123113
11422a20090969
121746a4389921
1389213812186
144211d085a77
1521336862e5d
hex11766c5ede9

1200020123113 has 4 divisors (see below), whose sum is σ = 1371451569280. Its totient is φ = 1028588676948.

The previous prime is 1200020123111. The next prime is 1200020123129. The reversal of 1200020123113 is 3113210200021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1200020123113 - 21 = 1200020123111 is a prime.

It is a super-2 number, since 2×12000201231132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200020123111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85715723073 + ... + 85715723086.

It is an arithmetic number, because the mean of its divisors is an integer number (342862892320).

Almost surely, 21200020123113 is an apocalyptic number.

It is an amenable number.

1200020123113 is a deficient number, since it is larger than the sum of its proper divisors (171431446167).

1200020123113 is an equidigital number, since it uses as much as digits as its factorization.

1200020123113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 171431446166.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1200020123113 its reverse (3113210200021), we get a palindrome (4313230323134).

The spelling of 1200020123113 in words is "one trillion, two hundred billion, twenty million, one hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 7 171431446159 1200020123113