120002023000113 has 16 divisors (see below), whose sum is σ = 160178286290880. Its totient is φ = 79913594428416.

The previous prime is 120002023000109. The next prime is 120002023000133. The reversal of 120002023000113 is 311000320200021.

It is not a de Polignac number, because 120002023000113 - 2² = 120002023000109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120002023000092 and 120002023000101.

It is not an unprimeable number, because it can be changed into a prime (120002023000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6905833 + ... + 16961561.

It is an arithmetic number, because the mean of its divisors is an integer number (10011142893180).

Almost surely, 2^{120002023000113} is an apocalyptic number.

It is an amenable number.

120002023000113 is a deficient number, since it is larger than the sum of its proper divisors (40176263290767).

120002023000113 is a wasteful number, since it uses less digits than its factorization.

120002023000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10060096.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 120002023000113 its reverse (311000320200021), we get a palindrome (431002343200134).

The spelling of 120002023000113 in words is "one hundred twenty trillion, two billion, twenty-three million, one hundred thirteen", and thus it is an aban number.