Base | Representation |
---|---|
bin | 11011010010010000100110… |
… | …011100011001110010110011 |
3 | 120201220002012212220012212001 |
4 | 123102100212130121302303 |
5 | 111212103124443331011 |
6 | 1103120101101114431 |
7 | 34163601126306661 |
oct | 3322204634316263 |
9 | 521802185805761 |
10 | 120002031230131 |
11 | 352666372014a6 |
12 | 11561245558a17 |
13 | 51c61b21b9bab |
14 | 218c1b4b37c31 |
15 | dd17dcb367c1 |
hex | 6d2426719cb3 |
120002031230131 has 4 divisors (see below), whose sum is σ = 122928910040664. Its totient is φ = 117075152419600.
The previous prime is 120002031230119. The next prime is 120002031230141. The reversal of 120002031230131 is 131032130200021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 120002031230131 - 213 = 120002031221939 is a prime.
It is a super-2 number, since 2×1200020312301312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 120002031230099 and 120002031230108.
It is not an unprimeable number, because it can be changed into a prime (120002031230111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1463439405205 + ... + 1463439405286.
It is an arithmetic number, because the mean of its divisors is an integer number (30732227510166).
Almost surely, 2120002031230131 is an apocalyptic number.
120002031230131 is a deficient number, since it is larger than the sum of its proper divisors (2926878810533).
120002031230131 is an equidigital number, since it uses as much as digits as its factorization.
120002031230131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2926878810532.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 120002031230131 its reverse (131032130200021), we get a palindrome (251034161430152).
The spelling of 120002031230131 in words is "one hundred twenty trillion, two billion, thirty-one million, two hundred thirty thousand, one hundred thirty-one".
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