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120002303002011 = 340000767667337
BaseRepresentation
bin11011010010010000110110…
…101001001000010110011011
3120201220002220211021122210020
4123102100312221020112123
5111212104204032031021
61103120144050121523
734163610636320553
oct3322206651102633
9521802824248706
10120002303002011
1135266766655761
12115613005802a3
1351c62265b3361
14218c1dcc80163
15dd180691b7c6
hex6d2436a4859b

120002303002011 has 4 divisors (see below), whose sum is σ = 160003070669352. Its totient is φ = 80001535334672.

The previous prime is 120002303002009. The next prime is 120002303002027. The reversal of 120002303002011 is 110200303200021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120002303002011 - 21 = 120002303002009 is a prime.

It is not an unprimeable number, because it can be changed into a prime (120002303002051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20000383833666 + ... + 20000383833671.

It is an arithmetic number, because the mean of its divisors is an integer number (40000767667338).

Almost surely, 2120002303002011 is an apocalyptic number.

120002303002011 is a deficient number, since it is larger than the sum of its proper divisors (40000767667341).

120002303002011 is an equidigital number, since it uses as much as digits as its factorization.

120002303002011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40000767667340.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 120002303002011 its reverse (110200303200021), we get a palindrome (230202606202032).

The spelling of 120002303002011 in words is "one hundred twenty trillion, two billion, three hundred three million, two thousand, eleven".

Divisors: 1 3 40000767667337 120002303002011