Base | Representation |
---|---|
bin | 10001011101100110111… |
… | …100111000100110110001 |
3 | 11020201110200012022211122 |
4 | 101131212330320212301 |
5 | 124130121404041423 |
6 | 2315141043552025 |
7 | 152461456103210 |
oct | 21354674704661 |
9 | 4221420168748 |
10 | 1200023112113 |
11 | 422a21842611 |
12 | 1746a538b615 |
13 | 8921431a807 |
14 | 4211d623077 |
15 | 21336c538c8 |
hex | 11766f389b1 |
1200023112113 has 16 divisors (see below), whose sum is σ = 1413026004096. Its totient is φ = 997703007360.
The previous prime is 1200023112107. The next prime is 1200023112121. The reversal of 1200023112113 is 3112113200021.
It is a cyclic number.
It is not a de Polignac number, because 1200023112113 - 26 = 1200023112049 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1200023112091 and 1200023112100.
It is not an unprimeable number, because it can be changed into a prime (1200023112143) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12034931 + ... + 12134232.
It is an arithmetic number, because the mean of its divisors is an integer number (88314125256).
Almost surely, 21200023112113 is an apocalyptic number.
It is an amenable number.
1200023112113 is a deficient number, since it is larger than the sum of its proper divisors (213002891983).
1200023112113 is a wasteful number, since it uses less digits than its factorization.
1200023112113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24169384.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 1200023112113 its reverse (3112113200021), we get a palindrome (4312136312134).
The spelling of 1200023112113 in words is "one trillion, two hundred billion, twenty-three million, one hundred twelve thousand, one hundred thirteen".
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