Base | Representation |
---|---|
bin | 10001011101100110111… |
… | …101010011101101011011 |
3 | 11020201110200101222010102 |
4 | 101131212331103231123 |
5 | 124130121421120011 |
6 | 2315141050210015 |
7 | 152461460044655 |
oct | 21354675235533 |
9 | 4221420358112 |
10 | 1200023223131 |
11 | 422a21908a67 |
12 | 1746a542390b |
13 | 892143591c5 |
14 | 4211d6516d5 |
15 | 21336c7673b |
hex | 11766f53b5b |
1200023223131 has 6 divisors (see below), whose sum is σ = 1228579753860. Its totient is φ = 1172115704508.
The previous prime is 1200023223121. The next prime is 1200023223163. The reversal of 1200023223131 is 1313223200021.
It is not a de Polignac number, because 1200023223131 - 226 = 1199956114267 is a prime.
It is a super-2 number, since 2×12000232231312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1200023223121) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 324504161 + ... + 324507858.
It is an arithmetic number, because the mean of its divisors is an integer number (204763292310).
Almost surely, 21200023223131 is an apocalyptic number.
1200023223131 is a deficient number, since it is larger than the sum of its proper divisors (28556530729).
1200023223131 is an frugal number, since it uses more digits than its factorization.
1200023223131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 649012105 (or 649012062 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 1200023223131 its reverse (1313223200021), we get a palindrome (2513246423152).
The spelling of 1200023223131 in words is "one trillion, two hundred billion, twenty-three million, two hundred twenty-three thousand, one hundred thirty-one".
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