Base | Representation |
---|---|
bin | 1010111010100000101100… |
… | …0011101100110011000011 |
3 | 1120111012221020000100012202 |
4 | 2232220023003230303003 |
5 | 3033103130440104243 |
6 | 41304512305343415 |
7 | 2345665135131464 |
oct | 256501303546303 |
9 | 46435836010182 |
10 | 12000324144323 |
11 | 390734414a279 |
12 | 14198b0337b6b |
13 | 6908198c2268 |
14 | 2d6b66a78d6b |
15 | 15c2515ed4b8 |
hex | aea0b0eccc3 |
12000324144323 has 4 divisors (see below), whose sum is σ = 12001952639160. Its totient is φ = 11998695649488.
The previous prime is 12000324144311. The next prime is 12000324144401. The reversal of 12000324144323 is 32344142300021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12000324144323 - 218 = 12000323882179 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12000324444323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 814236365 + ... + 814251102.
It is an arithmetic number, because the mean of its divisors is an integer number (3000488159790).
Almost surely, 212000324144323 is an apocalyptic number.
12000324144323 is a deficient number, since it is larger than the sum of its proper divisors (1628494837).
12000324144323 is an equidigital number, since it uses as much as digits as its factorization.
12000324144323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1628494836.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 12000324144323 its reverse (32344142300021), we get a palindrome (44344466444344).
The spelling of 12000324144323 in words is "twelve trillion, three hundred twenty-four million, one hundred forty-four thousand, three hundred twenty-three".
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