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12000332231113 = 17416892781293
BaseRepresentation
bin1010111010100000101110…
…0010100011000111001001
31120111012221210020012012111
42232220023202203013021
53033103140022343423
641304513154542321
72345665263642232
oct256501342430711
946435853205174
1012000332231113
113907348772a76
1214198b2b979a1
1369081b494045
142d6b67b82089
1515c25219960d
hexaea0b8a31c9

12000332231113 has 4 divisors (see below), whose sum is σ = 12007225014148. Its totient is φ = 11993439448080.

The previous prime is 12000332231087. The next prime is 12000332231117. The reversal of 12000332231113 is 31113223300021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3778968817849 + 8221363413264 = 1943957^2 + 2867292^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000332231113 - 25 = 12000332231081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12000332231117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3446388906 + ... + 3446392387.

It is an arithmetic number, because the mean of its divisors is an integer number (3001806253537).

Almost surely, 212000332231113 is an apocalyptic number.

It is an amenable number.

12000332231113 is a deficient number, since it is larger than the sum of its proper divisors (6892783035).

12000332231113 is an equidigital number, since it uses as much as digits as its factorization.

12000332231113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6892783034.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 12000332231113 its reverse (31113223300021), we get a palindrome (43113555531134).

The spelling of 12000332231113 in words is "twelve trillion, three hundred thirty-two million, two hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 1741 6892781293 12000332231113