Base | Representation |
---|---|
bin | 100011110000111… |
… | …0010100001110011 |
3 | 10002122002100110211 |
4 | 1013201302201303 |
5 | 4424202240201 |
6 | 315025004551 |
7 | 41511113020 |
oct | 10741624163 |
9 | 3078070424 |
10 | 1200040051 |
11 | 566433941 |
12 | 295a83757 |
13 | 161809792 |
14 | b5540547 |
15 | 70547651 |
hex | 47872873 |
1200040051 has 8 divisors (see below), whose sum is σ = 1371759104. Its totient is φ = 1028392200.
The previous prime is 1200040043. The next prime is 1200040073. The reversal of 1200040051 is 1500400021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1200040051 - 23 = 1200040043 is a prime.
It is a super-2 number, since 2×12000400512 = 2880192248008165202, which contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1200040031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25276 + ... + 55126.
It is an arithmetic number, because the mean of its divisors is an integer number (171469888).
Almost surely, 21200040051 is an apocalyptic number.
1200040051 is a deficient number, since it is larger than the sum of its proper divisors (171719053).
1200040051 is an equidigital number, since it uses as much as digits as its factorization.
1200040051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 35601.
The product of its (nonzero) digits is 40, while the sum is 13.
The square root of 1200040051 is about 34641.5942329449. The cubic root of 1200040051 is about 1062.6703914229.
Adding to 1200040051 its reverse (1500400021), we get a palindrome (2700440072).
The spelling of 1200040051 in words is "one billion, two hundred million, forty thousand, fifty-one".
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