120004042143113 has 8 divisors (see below), whose sum is σ = 120183746773248. Its totient is φ = 119824341646464.

The previous prime is 120004042143079. The next prime is 120004042143127. The reversal of 120004042143113 is 311341240400021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120004042143113 - 2⁶ = 120004042143049 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (120004042143173) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 59748320 + ... + 61724142.

It is an arithmetic number, because the mean of its divisors is an integer number (15022968346656).

Almost surely, 2^{120004042143113} is an apocalyptic number.

It is an amenable number.

120004042143113 is a deficient number, since it is larger than the sum of its proper divisors (179704630135).

120004042143113 is an equidigital number, since it uses as much as digits as its factorization.

120004042143113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2066743.

The product of its (nonzero) digits is 2304, while the sum is 26.

Adding to 120004042143113 its reverse (311341240400021), we get a palindrome (431345282543134).

The spelling of 120004042143113 in words is "one hundred twenty trillion, four billion, forty-two million, one hundred forty-three thousand, one hundred thirteen".