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120004211003 = 571210164993
BaseRepresentation
bin110111111000011001…
…1101111000100111011
3102110202022002112220112
41233300303233010323
53431232034223003
6131043522414535
711445546651245
oct1576063570473
9373668075815
10120004211003
1146991280996
121b31120144b
13b41602cca1
145b45b21095
1531c55383d8
hex1bf0cef13b

120004211003 has 4 divisors (see below), whose sum is σ = 120214376568. Its totient is φ = 119794045440.

The previous prime is 120004210999. The next prime is 120004211051. The reversal of 120004211003 is 300112400021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120004211003 - 22 = 120004210999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120004211053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105081926 + ... + 105083067.

It is an arithmetic number, because the mean of its divisors is an integer number (30053594142).

Almost surely, 2120004211003 is an apocalyptic number.

120004211003 is a deficient number, since it is larger than the sum of its proper divisors (210165565).

120004211003 is an equidigital number, since it uses as much as digits as its factorization.

120004211003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 210165564.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 120004211003 its reverse (300112400021), we get a palindrome (420116611024).

The spelling of 120004211003 in words is "one hundred twenty billion, four million, two hundred eleven thousand, three".

Divisors: 1 571 210164993 120004211003