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1200044314121 = 19211299337569
BaseRepresentation
bin10001011101101000001…
…101110000111000001001
311020201112011002111112012
4101131220031300320021
5124130142321022441
62315143122225305
7152462134236512
oct21355015607011
94221464074465
101200044314121
11422a32803a34
121746b04b5235
1389218832093
1442122381a09
1521338a409eb
hex11768370e09

1200044314121 has 8 divisors (see below), whose sum is σ = 1269191296800. Its totient is φ = 1131496007040.

The previous prime is 1200044314087. The next prime is 1200044314123. The reversal of 1200044314121 is 1214134400021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1200044314121 - 26 = 1200044314057 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200044314123) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 149664776 + ... + 149672793.

It is an arithmetic number, because the mean of its divisors is an integer number (158648912100).

Almost surely, 21200044314121 is an apocalyptic number.

It is an amenable number.

1200044314121 is a deficient number, since it is larger than the sum of its proper divisors (69146982679).

1200044314121 is a wasteful number, since it uses less digits than its factorization.

1200044314121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 299337799.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1200044314121 its reverse (1214134400021), we get a palindrome (2414178714142).

The spelling of 1200044314121 in words is "one trillion, two hundred billion, forty-four million, three hundred fourteen thousand, one hundred twenty-one".

Divisors: 1 19 211 4009 299337569 5687413811 63160227059 1200044314121