12000848409241 has 4 divisors (see below), whose sum is σ = 12002533692084. Its totient is φ = 11999163126400.

The previous prime is 12000848409197. The next prime is 12000848409281. The reversal of 12000848409241 is 14290484800021.

12000848409241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6681501219600 + 5319347189641 = 2584860^2 + 2306371^2 .

It is a cyclic number.

It is not a de Polignac number, because 12000848409241 - 2⁴³ = 3204755387033 is a prime.

It is a super-3 number, since 3×12000848409241³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12000848409281) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 842630740 + ... + 842644981.

It is an arithmetic number, because the mean of its divisors is an integer number (3000633423021).

Almost surely, 2^{12000848409241} is an apocalyptic number.

It is an amenable number.

12000848409241 is a deficient number, since it is larger than the sum of its proper divisors (1685282843).

12000848409241 is an equidigital number, since it uses as much as digits as its factorization.

12000848409241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1685282842.

The product of its (nonzero) digits is 147456, while the sum is 43.

The spelling of 12000848409241 in words is "twelve trillion, eight hundred forty-eight million, four hundred nine thousand, two hundred forty-one".