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12000889273 = 52322946251
BaseRepresentation
bin10110010110100111…
…10000100110111001
31010222100210100012111
423023103300212321
5144034211424043
65302500412321
7603251606242
oct131323604671
933870710174
1012000889273
1150a920980a
1223ab0a70a1
1311933b6519
1481bbadcc9
154a389909d
hex2cb4f09b9

12000889273 has 4 divisors (see below), whose sum is σ = 12023836048. Its totient is φ = 11977942500.

The previous prime is 12000889267. The next prime is 12000889279. The reversal of 12000889273 is 37298800021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12000889267) and next prime (12000889279).

It is a cyclic number.

It is not a de Polignac number, because 12000889273 - 229 = 11464018361 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12000889279) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11472603 + ... + 11473648.

It is an arithmetic number, because the mean of its divisors is an integer number (3005959012).

Almost surely, 212000889273 is an apocalyptic number.

It is an amenable number.

12000889273 is a deficient number, since it is larger than the sum of its proper divisors (22946775).

12000889273 is an equidigital number, since it uses as much as digits as its factorization.

12000889273 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22946774.

The product of its (nonzero) digits is 48384, while the sum is 40.

The spelling of 12000889273 in words is "twelve billion, eight hundred eighty-nine thousand, two hundred seventy-three".

Divisors: 1 523 22946251 12000889273