Search a number
-
+
1200100031113 = 5234129555739
BaseRepresentation
bin10001011101101011100…
…010010011101010001001
311020201200000221012212111
4101131223202103222021
5124130301101443423
62315152432342321
7152463411644644
oct21355342235211
94221600835774
101200100031113
11422a611a9a35
121747070a49a1
138922723c709
1442129926a5b
152133d89960d
hex1176b893a89

1200100031113 has 8 divisors (see below), whose sum is σ = 1202688048800. Its totient is φ = 1197513134208.

The previous prime is 1200100031071. The next prime is 1200100031131. The reversal of 1200100031113 is 3111300010021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200100031113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200100031093 and 1200100031102.

It is not an unprimeable number, because it can be changed into a prime (1200100031153) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1881598 + ... + 2437336.

It is an arithmetic number, because the mean of its divisors is an integer number (150336006100).

Almost surely, 21200100031113 is an apocalyptic number.

It is an amenable number.

1200100031113 is a deficient number, since it is larger than the sum of its proper divisors (2588017687).

1200100031113 is an equidigital number, since it uses as much as digits as its factorization.

1200100031113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 560391.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1200100031113 its reverse (3111300010021), we get a palindrome (4311400041134).

The spelling of 1200100031113 in words is "one trillion, two hundred billion, one hundred million, thirty-one thousand, one hundred thirteen".

Divisors: 1 523 4129 555739 2159467 290651497 2294646331 1200100031113