Base | Representation |
---|---|
bin | 10001011101101100001… |
… | …100001100101001010001 |
3 | 11020201200210121010102001 |
4 | 101131230030030221101 |
5 | 124130311404344213 |
6 | 2315153503554001 |
7 | 152463604202314 |
oct | 21355414145121 |
9 | 4221623533361 |
10 | 1200111012433 |
11 | 422a6741a403 |
12 | 17470a8bb901 |
13 | 892295b5b38 |
14 | 4212b18497b |
15 | 2133e8181dd |
hex | 1176c30ca51 |
1200111012433 has 8 divisors (see below), whose sum is σ = 1252388980800. Its totient is φ = 1147841313168.
The previous prime is 1200111012427. The next prime is 1200111012437. The reversal of 1200111012433 is 3342101110021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1200111012433 - 29 = 1200111011921 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1200111012433.
It is not an unprimeable number, because it can be changed into a prime (1200111012437) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1769778 + ... + 2352091.
It is an arithmetic number, because the mean of its divisors is an integer number (156548622600).
Almost surely, 21200111012433 is an apocalyptic number.
It is an amenable number.
1200111012433 is a deficient number, since it is larger than the sum of its proper divisors (52277968367).
1200111012433 is a wasteful number, since it uses less digits than its factorization.
1200111012433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4134551.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1200111012433 its reverse (3342101110021), we get a palindrome (4542212122454).
The spelling of 1200111012433 in words is "one trillion, two hundred billion, one hundred eleven million, twelve thousand, four hundred thirty-three".
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