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120011334457 = 7153111198221
BaseRepresentation
bin110111111000100111…
…0111010001100111001
3102110202210111110110011
41233301032322030321
53431240400200312
6131044335221521
711445664340320
oct1576116721471
9373683443404
10120011334457
11469952a6943
121b3136778a1
13b417655451
145b46a570b7
1531c5e93da7
hex1bf13ba339

120011334457 has 8 divisors (see below), whose sum is σ = 137245408832. Its totient is φ = 102799659600.

The previous prime is 120011334451. The next prime is 120011334463. The reversal of 120011334457 is 754433110021.

It is an interprime number because it is at equal distance from previous prime (120011334451) and next prime (120011334463).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120011334457 - 215 = 120011301689 is a prime.

It is not an unprimeable number, because it can be changed into a prime (120011334451) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5588394 + ... + 5609827.

It is an arithmetic number, because the mean of its divisors is an integer number (17155676104).

Almost surely, 2120011334457 is an apocalyptic number.

It is an amenable number.

120011334457 is a deficient number, since it is larger than the sum of its proper divisors (17234074375).

120011334457 is a wasteful number, since it uses less digits than its factorization.

120011334457 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11199759.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 120011334457 its reverse (754433110021), we get a palindrome (874444444478).

The spelling of 120011334457 in words is "one hundred twenty billion, eleven million, three hundred thirty-four thousand, four hundred fifty-seven".

Divisors: 1 7 1531 10717 11198221 78387547 17144476351 120011334457