1200114030113 has 4 divisors (see below), whose sum is σ = 1200159342228. Its totient is φ = 1200068718000.

The previous prime is 1200114030109. The next prime is 1200114030131. The reversal of 1200114030113 is 3110304110021.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 554506601104 + 645607429009 = 744652^2 + 803497^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200114030113 - 2² = 1200114030109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200114030091 and 1200114030100.

It is not an unprimeable number, because it can be changed into a prime (1200114030613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22616306 + ... + 22669307.

It is an arithmetic number, because the mean of its divisors is an integer number (300039835557).

Almost surely, 2^{1200114030113} is an apocalyptic number.

It is an amenable number.

1200114030113 is a deficient number, since it is larger than the sum of its proper divisors (45312115).

1200114030113 is an equidigital number, since it uses as much as digits as its factorization.

1200114030113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45312114.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1200114030113 its reverse (3110304110021), we get a palindrome (4310418140134).

The spelling of 1200114030113 in words is "one trillion, two hundred billion, one hundred fourteen million, thirty thousand, one hundred thirteen".