Search a number
-
+
1200114044011 = 3732435514703
BaseRepresentation
bin10001011101101100010…
…111110000110001101011
311020201201000022010221201
4101131230113300301223
5124130313143402021
62315154052545031
7152463642026611
oct21355427606153
94221630263851
101200114044011
11422a69100043
1217470b922177
138922a10797c
144212b7336b1
152133ec16591
hex1176c5f0c6b

1200114044011 has 4 divisors (see below), whose sum is σ = 1232549558752. Its totient is φ = 1167678529272.

The previous prime is 1200114044009. The next prime is 1200114044023. The reversal of 1200114044011 is 1104404110021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1200114044011 - 21 = 1200114044009 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1200114044011.

It is not an unprimeable number, because it can be changed into a prime (1200114044411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16217757315 + ... + 16217757388.

It is an arithmetic number, because the mean of its divisors is an integer number (308137389688).

Almost surely, 21200114044011 is an apocalyptic number.

1200114044011 is a deficient number, since it is larger than the sum of its proper divisors (32435514741).

1200114044011 is an equidigital number, since it uses as much as digits as its factorization.

1200114044011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32435514740.

The product of its (nonzero) digits is 128, while the sum is 19.

Adding to 1200114044011 its reverse (1104404110021), we get a palindrome (2304518154032).

The spelling of 1200114044011 in words is "one trillion, two hundred billion, one hundred fourteen million, forty-four thousand, eleven".

Divisors: 1 37 32435514703 1200114044011