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120012013011331 = 717144573287333
BaseRepresentation
bin11011010010011001111001…
…011001111000000110000011
3120201221000222112101020111001
4123102121321121320012003
5111212234100312330311
61103124431353232431
734164403363121620
oct3322317131700603
9521830875336431
10120012013011331
113526a899702451
1211563170402717
1351c71131988bc
14218c8806b7347
15dd1bc40e64c1
hex6d2679678183

120012013011331 has 4 divisors (see below), whose sum is σ = 137156586298672. Its totient is φ = 102867439723992.

The previous prime is 120012013011269. The next prime is 120012013011343. The reversal of 120012013011331 is 133110310210021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120012013011331 - 237 = 119874574057859 is a prime.

It is a super-3 number, since 3×1200120130113313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120012013011299 and 120012013011308.

It is not an unprimeable number, because it can be changed into a prime (120012013011391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8572286643660 + ... + 8572286643673.

It is an arithmetic number, because the mean of its divisors is an integer number (34289146574668).

Almost surely, 2120012013011331 is an apocalyptic number.

120012013011331 is a deficient number, since it is larger than the sum of its proper divisors (17144573287341).

120012013011331 is an equidigital number, since it uses as much as digits as its factorization.

120012013011331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17144573287340.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 120012013011331 its reverse (133110310210021), we get a palindrome (253122323221352).

The spelling of 120012013011331 in words is "one hundred twenty trillion, twelve billion, thirteen million, eleven thousand, three hundred thirty-one".

Divisors: 1 7 17144573287333 120012013011331