Search a number
-
+
1200120202011 = 3400040067337
BaseRepresentation
bin10001011101101100101…
…111010000001100011011
311020201201102220000010210
4101131230233100030123
5124130321232431021
62315154432542203
7152464045255143
oct21355457201433
94221642800123
101200120202011
11422a716266a5
121747119b1963
138922b482863
144212c497923
1521340530e76
hex1176cbd031b

1200120202011 has 4 divisors (see below), whose sum is σ = 1600160269352. Its totient is φ = 800080134672.

The previous prime is 1200120202009. The next prime is 1200120202019. The reversal of 1200120202011 is 1102020210021.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1200120202011 - 21 = 1200120202009 is a prime.

It is a super-4 number, since 4×12001202020114 (a number of 49 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1200120202019) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200020033666 + ... + 200020033671.

It is an arithmetic number, because the mean of its divisors is an integer number (400040067338).

Almost surely, 21200120202011 is an apocalyptic number.

1200120202011 is a deficient number, since it is larger than the sum of its proper divisors (400040067341).

1200120202011 is an equidigital number, since it uses as much as digits as its factorization.

1200120202011 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 400040067340.

The product of its (nonzero) digits is 16, while the sum is 12.

Adding to 1200120202011 its reverse (1102020210021), we get a palindrome (2302140412032).

The spelling of 1200120202011 in words is "one trillion, two hundred billion, one hundred twenty million, two hundred two thousand, eleven".

Divisors: 1 3 400040067337 1200120202011