120012143314131 has 6 divisors (see below), whose sum is σ = 173350873675980. Its totient is φ = 80008095542748.

The previous prime is 120012143314127. The next prime is 120012143314223. The reversal of 120012143314131 is 131413341210021.

120012143314131 is a `hidden beast` number, since 1 + 2 + 0 + 0 + 1 + 214 + 3 + 31 + 413 + 1 = 666.

It is not a de Polignac number, because 120012143314131 - 2² = 120012143314127 is a prime.

It is a super-2 number, since 2×120012143314131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120012143314095 and 120012143314104.

It is not an unprimeable number, because it can be changed into a prime (120012143314031) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 6667341295221 + ... + 6667341295238.

It is an arithmetic number, because the mean of its divisors is an integer number (28891812279330).

Almost surely, 2^{120012143314131} is an apocalyptic number.

120012143314131 is a deficient number, since it is larger than the sum of its proper divisors (53338730361849).

120012143314131 is a wasteful number, since it uses less digits than its factorization.

120012143314131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13334682590465 (or 13334682590462 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 120012143314131 its reverse (131413341210021), we get a palindrome (251425484524152).

It can be divided in two parts, 12001214 and 3314131, that added together give a triangular number (15315345 = T₅₅₃₄).

The spelling of 120012143314131 in words is "one hundred twenty trillion, twelve billion, one hundred forty-three million, three hundred fourteen thousand, one hundred thirty-one".