Base | Representation |
---|---|
bin | 1010111010100100010100… |
… | …1110101011010011010001 |
3 | 1120111022110020110001010121 |
4 | 2232221011032223103101 |
5 | 3033112130311202210 |
6 | 41305153211430241 |
7 | 2346031255461265 |
oct | 256510516532321 |
9 | 46438406401117 |
10 | 12001300100305 |
11 | 39077a504046a |
12 | 1419b23155381 |
13 | 690943b613c9 |
14 | 2d6c1a5280a5 |
15 | 15c2ac1306da |
hex | aea453ab4d1 |
12001300100305 has 16 divisors (see below), whose sum is σ = 15165583868160. Its totient is φ = 9099350301888.
The previous prime is 12001300100291. The next prime is 12001300100333. The reversal of 12001300100305 is 50300100310021.
12001300100305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 12001300100305 - 27 = 12001300100177 is a prime.
It is a super-2 number, since 2×120013001003052 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 478699077 + ... + 478724146.
It is an arithmetic number, because the mean of its divisors is an integer number (947848991760).
Almost surely, 212001300100305 is an apocalyptic number.
It is an amenable number.
12001300100305 is a deficient number, since it is larger than the sum of its proper divisors (3164283767855).
12001300100305 is a wasteful number, since it uses less digits than its factorization.
12001300100305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 957423360.
The product of its (nonzero) digits is 90, while the sum is 16.
Adding to 12001300100305 its reverse (50300100310021), we get a palindrome (62301400410326).
The spelling of 12001300100305 in words is "twelve trillion, one billion, three hundred million, one hundred thousand, three hundred five".
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