12001300100323 has 4 divisors (see below), whose sum is σ = 12001554719728. Its totient is φ = 12001045480920.

The previous prime is 12001300100291. The next prime is 12001300100333. The reversal of 12001300100323 is 32300100310021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12001300100323 - 2⁵ = 12001300100291 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12001300100297 and 12001300100306.

It is not an unprimeable number, because it can be changed into a prime (12001300100333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127238988 + ... + 127333273.

It is an arithmetic number, because the mean of its divisors is an integer number (3000388679932).

Almost surely, 2^{12001300100323} is an apocalyptic number.

12001300100323 is a deficient number, since it is larger than the sum of its proper divisors (254619405).

12001300100323 is an equidigital number, since it uses as much as digits as its factorization.

12001300100323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 254619404.

The product of its (nonzero) digits is 108, while the sum is 16.

Adding to 12001300100323 its reverse (32300100310021), we get a palindrome (44301400410344).

The spelling of 12001300100323 in words is "twelve trillion, one billion, three hundred million, one hundred thousand, three hundred twenty-three".