120013441101131 has 4 divisors (see below), whose sum is σ = 120340453202592. Its totient is φ = 119686428999672.

The previous prime is 120013441101041. The next prime is 120013441101161. The reversal of 120013441101131 is 131101144310021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 120013441101131 - 2¹⁸ = 120013440838987 is a prime.

It is a super-2 number, since 2×120013441101131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 120013441101097 and 120013441101106.

It is not an unprimeable number, because it can be changed into a prime (120013441101161) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 163506050180 + ... + 163506050913.

It is an arithmetic number, because the mean of its divisors is an integer number (30085113300648).

Almost surely, 2^{120013441101131} is an apocalyptic number.

120013441101131 is a deficient number, since it is larger than the sum of its proper divisors (327012101461).

120013441101131 is an equidigital number, since it uses as much as digits as its factorization.

120013441101131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327012101460.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 120013441101131 its reverse (131101144310021), we get a palindrome (251114585411152).

The spelling of 120013441101131 in words is "one hundred twenty trillion, thirteen billion, four hundred forty-one million, one hundred one thousand, one hundred thirty-one".