12001401021433 has 4 divisors (see below), whose sum is σ = 12001458937600. Its totient is φ = 12001343105268.

The previous prime is 12001401021409. The next prime is 12001401021523. The reversal of 12001401021433 is 33412010410021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12001401021433 - 2¹³ = 12001401013241 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12001401001433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28646133 + ... + 29062066.

It is an arithmetic number, because the mean of its divisors is an integer number (3000364734400).

Almost surely, 2^{12001401021433} is an apocalyptic number.

It is an amenable number.

12001401021433 is a deficient number, since it is larger than the sum of its proper divisors (57916167).

12001401021433 is an equidigital number, since it uses as much as digits as its factorization.

12001401021433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57916166.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 12001401021433 its reverse (33412010410021), we get a palindrome (45413411431454).

The spelling of 12001401021433 in words is "twelve trillion, one billion, four hundred one million, twenty-one thousand, four hundred thirty-three".