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12001413035 = 5113137155047
BaseRepresentation
bin10110010110101011…
…10000011110101011
31010222101202221200002
423023111300132223
5144034330204120
65302515533215
7603256220243
oct131325603653
933871687602
1012001413035
1150a9537277
1223ab2ba20b
13119353aa41
1481bca8b23
154a394e375
hex2cb5707ab

12001413035 has 16 divisors (see below), whose sum is σ = 14635290816. Its totient is φ = 9446642688.

The previous prime is 12001412977. The next prime is 12001413049. The reversal of 12001413035 is 53031410021.

It is a cyclic number.

It is not a de Polignac number, because 12001413035 - 28 = 12001412779 is a prime.

It is a super-2 number, since 2×120014130352 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12001412998 and 12001413016.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 119 + ... + 154928.

It is an arithmetic number, because the mean of its divisors is an integer number (914705676).

Almost surely, 212001413035 is an apocalyptic number.

12001413035 is a deficient number, since it is larger than the sum of its proper divisors (2633877781).

12001413035 is a wasteful number, since it uses less digits than its factorization.

12001413035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155302.

The product of its (nonzero) digits is 360, while the sum is 20.

Adding to 12001413035 its reverse (53031410021), we get a palindrome (65032823056).

The spelling of 12001413035 in words is "twelve billion, one million, four hundred thirteen thousand, thirty-five".

Divisors: 1 5 113 137 565 685 15481 77405 155047 775235 17520311 21241439 87601555 106207195 2400282607 12001413035