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120020124153 = 3116334399577
BaseRepresentation
bin110111111000111000…
…0011100000111111001
3102110210102001000122110
41233301300130013321
53431300122433103
6131045251442533
711446132136256
oct1576160340771
9373712030573
10120020124153
114699a25a756
121b3165b6449
13b419412157
145b47ca442d
1531c6b2d403
hex1bf1c1c1f9

120020124153 has 8 divisors (see below), whose sum is σ = 160164435168. Its totient is φ = 79944614624.

The previous prime is 120020124149. The next prime is 120020124181. The reversal of 120020124153 is 351421020021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 120020124153 - 22 = 120020124149 is a prime.

It is a super-3 number, since 3×1200201241533 (a number of 34 digits) contains 333 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (120020124113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17196300 + ... + 17203277.

It is an arithmetic number, because the mean of its divisors is an integer number (20020554396).

Almost surely, 2120020124153 is an apocalyptic number.

It is an amenable number.

120020124153 is a deficient number, since it is larger than the sum of its proper divisors (40144311015).

120020124153 is a wasteful number, since it uses less digits than its factorization.

120020124153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34400743.

The product of its (nonzero) digits is 480, while the sum is 21.

Adding to 120020124153 its reverse (351421020021), we get a palindrome (471441144174).

The spelling of 120020124153 in words is "one hundred twenty billion, twenty million, one hundred twenty-four thousand, one hundred fifty-three".

Divisors: 1 3 1163 3489 34399577 103198731 40006708051 120020124153