120022021010113 has 4 divisors (see below), whose sum is σ = 120022093685808. Its totient is φ = 120021948334420.

The previous prime is 120022021010093. The next prime is 120022021010117. The reversal of 120022021010113 is 311010120220021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 120022021010113 - 2⁴⁵ = 84837648921281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (120022021010117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33801631 + ... + 37183252.

It is an arithmetic number, because the mean of its divisors is an integer number (30005523421452).

Almost surely, 2^{120022021010113} is an apocalyptic number.

It is an amenable number.

120022021010113 is a deficient number, since it is larger than the sum of its proper divisors (72675695).

120022021010113 is an equidigital number, since it uses as much as digits as its factorization.

120022021010113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 72675694.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 120022021010113 its reverse (311010120220021), we get a palindrome (431032141230134).

The spelling of 120022021010113 in words is "one hundred twenty trillion, twenty-two billion, twenty-one million, ten thousand, one hundred thirteen".