Base | Representation |
---|---|
bin | 10110010110110010… |
… | …10011110011000011 |
3 | 1010222110112020220010 |
4 | 23023121103303003 |
5 | 144040100003011 |
6 | 5302551520003 |
7 | 603300145641 |
oct | 131331236303 |
9 | 33873466803 |
10 | 12002344131 |
11 | 50aa012878 |
12 | 23ab689003 |
13 | 11937a579b |
14 | 81c06c191 |
15 | 4a3a851a6 |
hex | 2cb653cc3 |
12002344131 has 8 divisors (see below), whose sum is σ = 16944485904. Its totient is φ = 7530882560.
The previous prime is 12002344103. The next prime is 12002344243. The reversal of 12002344131 is 13144320021.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12002344131 - 226 = 11935235267 is a prime.
It is a super-2 number, since 2×120023441312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12002344098 and 12002344107.
It is not an unprimeable number, because it can be changed into a prime (12002344831) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 117669990 + ... + 117670091.
It is an arithmetic number, because the mean of its divisors is an integer number (2118060738).
Almost surely, 212002344131 is an apocalyptic number.
12002344131 is a deficient number, since it is larger than the sum of its proper divisors (4942141773).
12002344131 is a wasteful number, since it uses less digits than its factorization.
12002344131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 235340101.
The product of its (nonzero) digits is 576, while the sum is 21.
Adding to 12002344131 its reverse (13144320021), we get a palindrome (25146664152).
The spelling of 12002344131 in words is "twelve billion, two million, three hundred forty-four thousand, one hundred thirty-one".
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