Base | Representation |
---|---|
bin | 10110010110111000… |
… | …00000001111000001 |
3 | 1010222111212010202110 |
4 | 23023130000033001 |
5 | 144040240103213 |
6 | 5303015005533 |
7 | 603306150063 |
oct | 131334001701 |
9 | 33874763673 |
10 | 12003050433 |
11 | 50aa4554a0 |
12 | 23ab9698a9 |
13 | 119399210a |
14 | 81c1b3733 |
15 | 4a3b745c3 |
hex | 2cb7003c1 |
12003050433 has 16 divisors (see below), whose sum is σ = 17474500800. Its totient is φ = 7268110080.
The previous prime is 12003050431. The next prime is 12003050441. The reversal of 12003050433 is 33405030021.
It is not a de Polignac number, because 12003050433 - 21 = 12003050431 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12003050431) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 123828 + ... + 198341.
It is an arithmetic number, because the mean of its divisors is an integer number (1092156300).
Almost surely, 212003050433 is an apocalyptic number.
It is an amenable number.
12003050433 is a deficient number, since it is larger than the sum of its proper divisors (5471450367).
12003050433 is a wasteful number, since it uses less digits than its factorization.
12003050433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 323312.
The product of its (nonzero) digits is 1080, while the sum is 21.
Adding to 12003050433 its reverse (33405030021), we get a palindrome (45408080454).
The spelling of 12003050433 in words is "twelve billion, three million, fifty thousand, four hundred thirty-three".
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