1200311113 has 4 divisors (see below), whose sum is σ = 1200728340. Its totient is φ = 1199893888.

The previous prime is 1200311107. The next prime is 1200311141. The reversal of 1200311113 is 3111130021.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3111130021 = 1283 ⋅2424887.

It can be written as a sum of positive squares in 2 ways, for example, as 480354889 + 719956224 = 21917^2 + 26832^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1200311113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1200311093 and 1200311102.

It is not an unprimeable number, because it can be changed into a prime (1200311153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204268 + ... + 210061.

It is an arithmetic number, because the mean of its divisors is an integer number (300182085).

Almost surely, 2^1200311113 is an apocalyptic number.

It is an amenable number.

1200311113 is a deficient number, since it is larger than the sum of its proper divisors (417227).

1200311113 is an equidigital number, since it uses as much as digits as its factorization.

1200311113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 417226.

The product of its (nonzero) digits is 18, while the sum is 13.

The square root of 1200311113 is about 34645.5063897181. The cubic root of 1200311113 is about 1062.7503964961.

Adding to 1200311113 its reverse (3111130021), we get a palindrome (4311441134).

The spelling of 1200311113 in words is "one billion, two hundred million, three hundred eleven thousand, one hundred thirteen".