12003121330321 has 4 divisors (see below), whose sum is σ = 13094314178544. Its totient is φ = 10911928482100.

The previous prime is 12003121330259. The next prime is 12003121330351. The reversal of 12003121330321 is 12303312130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003121330321 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12003121330292 and 12003121330301.

It is not an unprimeable number, because it can be changed into a prime (12003121330351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 545596424095 + ... + 545596424116.

It is an arithmetic number, because the mean of its divisors is an integer number (3273578544636).

Almost surely, 2^{12003121330321} is an apocalyptic number.

12003121330321 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

12003121330321 is a deficient number, since it is larger than the sum of its proper divisors (1091192848223).

12003121330321 is a wasteful number, since it uses less digits than its factorization.

12003121330321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1091192848222.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 12003121330321 its reverse (12303312130021), we get a palindrome (24306433460342).

The spelling of 12003121330321 in words is "twelve trillion, three billion, one hundred twenty-one million, three hundred thirty thousand, three hundred twenty-one".