12003131312113 has 4 divisors (see below), whose sum is σ = 12003638588928. Its totient is φ = 12002624035300.

The previous prime is 12003131312033. The next prime is 12003131312119. The reversal of 12003131312113 is 31121313130021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003131312113 is a prime.

It is a super-2 number, since 2×12003131312113² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12003131312119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 253602913 + ... + 253650238.

It is an arithmetic number, because the mean of its divisors is an integer number (3000909647232).

Almost surely, 2^{12003131312113} is an apocalyptic number.

It is an amenable number.

12003131312113 is a deficient number, since it is larger than the sum of its proper divisors (507276815).

12003131312113 is an equidigital number, since it uses as much as digits as its factorization.

12003131312113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 507276814.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 12003131312113 its reverse (31121313130021), we get a palindrome (43124444442134).

The spelling of 12003131312113 in words is "twelve trillion, three billion, one hundred thirty-one million, three hundred twelve thousand, one hundred thirteen".