1200320111323 has 4 divisors (see below), whose sum is σ = 1216762852648. Its totient is φ = 1183877370000.

The previous prime is 1200320111311. The next prime is 1200320111329. The reversal of 1200320111323 is 3231110230021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1200320111323 - 2³⁷ = 1062881157851 is a prime.

It is a super-2 number, since 2×1200320111323² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1200320111323.

It is not an unprimeable number, because it can be changed into a prime (1200320111329) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8221370553 + ... + 8221370698.

It is an arithmetic number, because the mean of its divisors is an integer number (304190713162).

Almost surely, 2^{1200320111323} is an apocalyptic number.

1200320111323 is a deficient number, since it is larger than the sum of its proper divisors (16442741325).

1200320111323 is an equidigital number, since it uses as much as digits as its factorization.

1200320111323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16442741324.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1200320111323 its reverse (3231110230021), we get a palindrome (4431430341344).

The spelling of 1200320111323 in words is "one trillion, two hundred billion, three hundred twenty million, one hundred eleven thousand, three hundred twenty-three".